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“Numerical Ability & Quantitative Comparison” portion of Part A (General Aptitude) of CSIR-UGC NET/JRF/Ph.D.

 Below is a compact but exam-oriented set of class notes for the “Numerical Ability & Quantitative Comparison” portion of Part A (General Aptitude) of CSIR-UGC NET/JRF/Ph.D. examinations. The outline follows the official Part A syllabus and question trends.


1. Question Types Asked

TypeWhat you must doTypical weight
Numerical computationEvaluate an arithmetic/algebraic expression quickly3–5 Qs
Numerical estimationApproximate square-roots, percentages, ratios2–3 Qs
Series completionIdentify pattern and fill the next term1–2 Qs
Quantitative comparisonDecide which of two quantities is larger/equal/indeterminable3–4 Qs
Data sufficiencyJudge whether given statements are adequate to answer a value1–2 Qs
Ration–proportion, averages, mixturesSolve everyday arithmetic setups2–3 Qs
Time–work, speed–distanceApply LCM approach or relative speed1–2 Qs
(Distribution derived from the last 10 papers’ blueprint.)diwakareducationhub+1

2. Core Techniques & Short-Cuts

  1. Vedic splits for fast multiplication

    • 992=(1001)2=10,000200+1=9,80199^2 = (100-1)^2 = 10,000-200+1 = 9,801

    • Unit-digit rule for a×b ending in 5: e.g., 65×35=6×325=225=2,27565×35 = 6×3 | 25 = 2 | 25 = 2,275.

  2. “5-second” fraction ↔ percentage table
    1/3 = 33⅓%, 2/3 = 66⅔%, 1/8 = 12.5%, 3/8 = 37.5%, 5/8 = 62.5%, 7/8 = 87.5%.

  3. Ratio blend for mixtures
    Final ratio = (difference of parts opposite the ingredient) ⇒
    Milk:water target 3:1 from pure milk & 50% mix → mix 1 : 1.

  4. Successive percentage change
    Net % = a+b+ab100a + b + \dfrac{ab}{100}.
    Example: 20% hike then 10% discount → 20102=820 – 10 – 2 = 8% rise.

  5. Relative speed (trains)
    Crossing time = (sum or difference of lengths)/relative speed.
    Convert km h⁻¹ to m s⁻¹ by × 5/18.

  6. “LCM triangle” for work
    Take LCM of individual days → allocate work units → add rates.

  7. Quantitative comparison decision tree

    • If both quantities simplify to the same expression → equal.

    • If expressions differ in sign domain, test boundary values.

    • If indeterminate, mark “Cannot be determined”.


3. Must-Remember Formulae

ThemeFormula
n-term AP sumSn=n(a1+an)/2S_n = n(a_1+a_n)/2
n-term GP sumSn=a(rn1)/(r1)S_n = a(r^n-1)/(r-1)
Simple interestSI=PRT/100SI = PRT/100
Compound interestA=P(1+rn)ntA = P\,(1+\tfrac{r}{n})^{nt}
PermutationsnPr=n!/(nr)!^{n}P_{r}= n!/(n-r)!
CombinationsnCr=n!/[(nr)!r!]^{n}C_{r}= n!/[(n-r)!r!]
Mean–variance linkฯƒ2=E(X2)[E(X)]2\sigma^2 = E(X^2) - [E(X)]^2
Keep these on a single flash-card for last-minute revision.

4. Practice Drill (5 Sample Qs)

  1. Numerical estimation
    Evaluate 2025\sqrt{2025} without calculator.

    • Trick: 45² = 2,025 ⇒ answer 45.

  2. Quantitative comparison
    Quantity A: 5117\frac{51}{17}, Quantity B: 3. Decision?

    • Both equal ⇒ mark “A = B”.

  3. Series completion
    3, 7, 15, 31, __?

    • Pattern ×2 + 1 ⇒ next = 63.

  4. Mixture problem
    How many L of water must be added to 20 L of 60% acid to obtain 40% acid?

    • Acid litres = 12. Need total 30 L ⇒ add 10 L water.

  5. Relative speed
    Two trains 180 m & 120 m long cross opposite each other in 12 s at 45 km h⁻¹ & ? km h⁻¹. Find second speed.

    • Relative speed =(180+120)/12=25ms1=90kmh1= (180+120)/12 = 25 m s⁻¹ = 90 km h⁻¹.

    • So second speed = 90 – 45 = 45 km h⁻¹.

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